Java - OverridingIn the previous chapter, we talked about superclasses and subclasses. If a class inherits a method from its superclass, then there is a chance to override the method provided that it is not marked final. The benefit of overriding is: ability to define a behavior that's specific to the subclass type which means a subclass can implement a parent class method based on its requirement. In object-oriented terms, overriding means to override the functionality of an existing method. Example: Let us look at an example.
classAnimal{
public void move(){ System.out.println("Animals can move"); } } class Dog extends Animal{ public void move(){ System.out.println("Dogs can walk and run"); } } public class TestDog{ public static void main(String args[]){ Animal a =new Animal();// Animal reference and object Animal b =new Dog();// Animal reference but Dog object a.move();// runs the method in Animal class b.move();//Runs the method in Dog class } } This would produce the following result:
Animals can move
Dogs can walk and run In the above example, you can see that the even though b is a type of Animal it runs the move method in the Dog class. The reason for this is: In compile time, the check is made on the reference type. However, in the runtime, JVM figures out the object type and would run the method that belongs to that particular object. Therefore, in the above example, the program will compile properly since Animal class has the method move. Then, at the runtime, it runs the method specific for that object. Consider the following example:
class Animal{
public void move(){ System.out.println("Animals can move"); } } class Dog extendsAnimal{ public void move(){ System.out.println("Dogs can walk and run"); } public void bark(){ System.out.println("Dogs can bark"); } } public class TestDog{ public static void main(String args[]){ Animal a =new Animal();// Animal reference and object Animal b =new Dog();// Animal reference but Dog object a.move();// runs the method in Animal class b.move();//Runs the method in Dog class b.bark(); } } This would produce the following result:
TestDog.java:30: cannot find symbol
symbol : method bark() location:class Animal b.bark(); ^ This program will throw a compile time error since b's reference type Animal doesn't have a method by the name of bark. Rules for method overriding:
When invoking a superclass version of an overridden method the super keyword is used.
class Animal{
public void move(){ System.out.println("Animals can move"); } } class Dog extends Animal{ public void move(){ super.move();// invokes the super class method System.out.println("Dogs can walk and run"); } } public class TestDog{ public static void main(String args[]){ Animal b =new Dog();// Animal reference but Dog object b.move();//Runs the method in Dog class } } This would produce the following result:
Animals can move
Dogs can walk and run |